On the freefall time, the 3+ minute estimate is a bit off.
s=ut + 0.5at^2, assuming an initial vertical velocity of 0, and initial height s=8000m (I can't be bothered to convert 35,000' to m), would be around 40s.
40s accelerating at 10 ms^-2 is a final velocity of 400 ms^-1. Terminal velocities are typically less than 100 ms^-1.