Originally Posted by
roulishollandais
Not only the centerline is going away, but the slope too !
Hmmm so the ground-glide has that angle Å | tg Å = tg4°× 143 / 115.7
Å = 4° 56 ' ??
As the lens (to which the 4° are held) is moving and therefore the 4° would be against the slower moving deck, I would say it is the inverse.
Effective glide angle would be 3° 14,4' over ground.