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Old 26th Apr 2013, 22:24
  #318 (permalink)  
keith williams
 
Join Date: Jan 2011
Location: England
Posts: 661
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You have not provided sufficient information to solve the problem. But the two examples below illustrate the general method for solving these types of problems.

Example 1.
An aircraft has a floor load limit of 4500 N/m squared. What is the maximum mass that can be loaded in this hold on a 1.4m x 0.4m pallet? (g = 9.81 m/s/s).

(a) 464 Kg.
(b) 122 Kg.
(c) 177 Kg.
(d) 256 Kg.


The floor loading limit is 4500 n/m squared and the floor area of the pallet is 1.4m x 0.4m = 0.56m squared.

Floor loading = load / area.

So load required to exert a given floor loading = floor loading x area.

This means that the pallet load required to exert the limiting floor loading of 4500 N/m squared, is equal to 4500 N/m squared x 0.56 m squared = 2520 N.

The force exerted by a mass = F = mass x g
Rearranging this equation gives mass = F/g

Using g = 9.81, the mass required on the pallet must be 2520 N/9.81 = 256.9 Kg.



Example 2.
What is the maximum mass that can be loaded onto a 0.8m square 25 Kg pallet, if the running load limit is 800 Kg/m?

(a) 644 Kg.
(b) 615 Kg.
(c) 475 Kg.
(d) 519 Kg.

The running load exerted by a load is equal to the total mass of the load divided by the length of its base.

In order to obtain the maximum allowable mass, it is necessary to orient the pallet such that its longest possible base length is used.

If the mass loaded on the pallet = M, then the total mass is the load (M Kg) plus the pallet mass (25 Kg) which gives a total mass of (M + 25) Kg.

Both of the edges of the pallet are 0.8 m long.
So the running load exerted by the loaded pallet is:

Running Load = Total mass/ base length = (M + 25) Kg / 0.8m

But the maximum allowable running load in this question is 800 Kg/m, so the maximum mass that can be loaded on the pallet is that which gives the condition:

(M + 25) Kg / 0.8 m = 800Kg / m.

This equation can be simplified by multiplying both sides by 0.8 m, to give:

(M + 25) Kg = (0.8 x 800) Kg Which is 640 Kg

Subtracting 25 Kg from each side gives M = 615 Kg
So the maximum mass that can be loaded on the pallet is 615 Kg.


General factors to remember:

1. The static load intensity for any given load will be a minimum when the load is sitting on its largest side. So to maximize the permitted load, it must be placed on its largest side.

2. The running load imposed by any given load will be minimum when the load is moving along its longest side. So to maximize the permitted load, it must be moved along its longest side.
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