For the eggheads: The math behind an uncoordinated turn

[cwatters]

With reference to Superpilots diagrams..

For a correct turn with no loss of height..

Vertically..

mg = LCos(x)

Where

m=mass of aircraft
g = gravity
L = Lift
x = bank angle

Solve for L
L = mg/Cos(x) ...................... (1)

Horizontally..

mv^2/r = LSin(x)

where
v = velocity
r = radius of turn

Solve for L
L = mv^2/rSin(x) ......................(2)

Equate (1) and (2)

mg/Cos(x) = mv^2/rSin(x)

Mass cancels

rearrange

Sin(x)/Cos(x) = v^2/rg

Sin(x)/Cos(x) = Tan(x)

so I think in a normal turn

Tan(x) = v^2/rg

If Tan(x) > v^2/rg then it's a slip
If Tan(x) < v^2/rg then it's a skid

Someone check the maths :-)