PPRuNe Forums - View Single Post - india DGCA ATPL exam
View Single Post
Old 5th May 2012, 08:17
  #349 (permalink)  
gAMbl3
 
Join Date: Jul 2010
Location: Mumbai
Age: 34
Posts: 120
Likes: 0
Received 0 Likes on 0 Posts
Post 345 is plotting problem. You need a 'Geometry box' for solving it.

Referring to you diagram :

480 nm on 110E = 8 deg

So A is at 82N 110E

Keep one end of the divider on the North pole and the other at point A. Measure that distance on the scale which is say X cm.

If X cm = 480 nm then find how much it will be for 300 nm say Y cm.

Now keep the divider along 154(AR) such that one end is on point A. The other end which is Y cm from A will be the a/c position say point B. (300 nm along grid track 154)

Join B and N (north pole)

Measure that distance in cm with the divider and find how many nm it is say Z nm. 90 - Z/60 = Latitude of new postion.

Keep the protractor at N and measure angle PNB and subtract that value from 110E and that will be the Longitude of the new position.
gAMbl3 is offline