PPRuNe Forums - View Single Post - FAA ATPL test: CG shift in index arms
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Old 21st Apr 2012, 12:30
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pavil
 
Join Date: Jun 2002
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easiest way to solve it is using the equation;

weight to be shifted / total weight = Δcg / distance the weight is shifted

you are trying to work out the difference, which is the Δcg,

Δcg = ( weight to be shifted * distance the weight is shifted ) / total weight

we know the weight to be shifted is 3300 lbs,

the distance to be shifted is from fwd hold (-227.9) to aft hold (144.9), therefore the distance between these two holds is 144.9 plus 227.9, which gives us 372.8,

and the total weight is 88300 lbs.

so now Δcg = ( 3300 * 372.8 ) / 88300

Δcg = 13.93
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