1.Aircraft Height = 30,000 Ft which= 4.9NM (taking 6080 ft = 1 Nm)
2.Assuming VOR elevation angle of 40 degrees (default)
3.Using Trigonometry : (right angled Triangle)
a. Tan 40 Degrees = 4.9 NM / distance traveled (D)
b. D= 4.9 / Tan 40 Degrees therefore D= 5.8 NM
c. find Time taken At G/S of 300 Kts to cover 5.8 NM ?
d. time taken = (5.8 NM / 300 NM / hr ) x 2 = 2.32 approx to 2.25
