1 act QDM 330° act HDG 060° req QDM 350° Intercept HDG?
QDM 330
QDR = 330 - 180 = 150 (Seg AC)
So a/c on radial 150 (Point C)
req QDM = 350, QDR = 170 (Seg AD)
interception angle 45 deg (if angle is not mentioned). *answer to question 3*
angle CED = 45
AD parallel to BC
CD perpendicular to AD and BC
In triangle EDC, CED =
ECD = 45 deg and
EDC = 90 deg
DAC =
BCA = 20 deg (QDR 170 - QDR 150)
angle BCD = BCA + ACE + ECD
90 = 20 + ACE + 45
ACE = 25 deg
So if the a/c at point C on seg AC (QDM 330/QDR 150) and wants to intercept seg AD (QDM 350/QDR 170) at 45 deg, it will have to turn left to a heading of 330 - ACE = 330 - 25 = 305.
2 .act QDM 140° act HDG 020° req QDM 110° First turn?
Similarly
45 deg intecept
act QDM 140 + 15 = 155
ans : Right hdg 155 (dont know how 'Left')