Dick,
An example may help with some numbers ...
Say free stream M=1.5 with a wedge of
12 degrees = oblique shock
13 degrees = normal shock
Ratio is the relationship between the value before the shock to after the shock. p = static pressure, pt = total pressure, T =temperature, r = density
For the normal shock
Shock angle = 90 degrees
Mach = 0.701
p ratio = 2.458
pt ratio = 0.929
T ratio = 1.32
r ratio = 1.862
For the oblique shock
Shock angle = 64.371 degrees
Mach = 0.959
p ratio = 1.969
pt ratio = 0.969
T ratio = 1.224
r ratio = 1.608
Q -When comparing a normal and an oblique shockwave, the normal shockwave:
A) has a higher total pressure - no
B) has a higher total temperature - yes
C) has a lower static pressure - no
D) has a lower total pressure - no
The trick question is how in JAR does this improve delivering passengers and freight to the destination safely.
Regards
Z