I figured out number 3 and 4 by taking the TAS multiplies by wind speed and divide by 60.
Here is how I did it: 110*20/60 = 37
Then use the clock code to work out how much of that max drift actually applies. The clock code can be used by imagining a clock, taking the number of degrees the wind is off your nose and pretending these degrees are minutes on the clock face.
If the wind is 15 degrees off the nose look at the 15 minute mark on your clock face: 15 minutes is quarter of an hour so the drift you can expect is a quarter of the max drift you calculated before.
If the wind is 30 degrees off the nose, look at the 30 minute mark on your clock face: 30 minutes is half an hour so the drift you can expect is half the max drift you calculated before.
the wind is 73 degree off so it is 73 minutes on the clock and the maximum drift is (20*110)/60 = 36.6 or 37 degree.
73 minutes on the clock is about a quarter, so 37*1/4 = 9.25 or 9 degree. so the answers for number 3 is 93-9 = 84 and number 4 is 93+9+180 = 282.
But I am still having trouble with the first two questions.