The fore and aft distance between the two main wheels and the single tail wheel of an aircraft is 8m. The unloaded weight of the aircraft is 20kN and its centre of gravity is 0.5m behind the main wheels. Calculate the force on the tail wheel and on each main wheel.
CG is at 1/16th of the distance between main and tail wheel(s). So the main wheels together receive 15/16th of the resulting force or 9375 N each. The remaining 1/16th or 1250 N will be dealt to the tail wheel.
This will result in a momentum to CG from each side of 9375N*2*0,5m = 1250N*7,5m = 9375 Nm -> the A/C remains standing on the Apron.
Um..... did I spoil anything?
