PPRuNe Forums - View Single Post - Indigo Call letters for Freshers

15th Oct 2011, 10:57

#2059 (permalink)

ILSAPPCH

Join Date: Aug 2011

Location: on d edge

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Refer to image attached :

It can be solved with a bit of geometric help...
C.a=5*sin60=4.3
dep=10*cos60=5

now simply using tan [1/2 C.A]=h/[1/2dep]
calculated h=.093=0deg 5 min

add this to 60 deg N gives 6006 N[option B]

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