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Old 11th Oct 2011, 11:19
  #5 (permalink)  
abhimakam
 
Join Date: Aug 2010
Location: Tanzania
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Hi

4)I think u can google it or locate it in any ATP Nav books...
Meridoinal parts are used when we deal wid 2 points which are neither on the same lat nor on the same long.
There would be a trigonometrical formulated table to find the track and dist between the two points.

5) The ans u get (i.e. 21.47) is== Equatorial D- Polar D
hence
Polar D= Equatorial D-21.47
Work it on a piece of paper,and it will make sense.

1) Sun moves from west to east isnt it?? Ans is pretty simple.
Sun moves at 15 deg/ hr. And he wants us to cover the same dist as the sun.
dat is dep= d long cos lat
==180*60*cos60
=5400 nms.

And, Sun travels at 15 deg/hr so 180 deg of long in how many hrs??
=> 180/15= 12 hrs

Hence the req ground speed is D/T=> 5400/12= 450kts.

2) The emphasis here is given on (T). coz anything measured on a chart is a true bearing. i.e. G.C. QUJ or G.C. QTE

3) G.C. trks are given.
We know dat Initial G.C trk-Final G.C. Trk = Convergency
And C.A= Con/2
SO hence its 3 degs.
And to determine the hemisphere its best to draw them and see.
And the ans seems to be correct according to me.
abhimakam is offline