Q5. At 5.25nm frm threshold an a/c on an ILS Approach has a display showing it to be 4dots low on a 3 degree glidepath, using an angle of 0.15degree per dot of glideslope deviation and the 1 in 60 rule calculate the height of the a/c from the touchdown.
a.1375ft
b.1325ft
c.1450ft
d.1280ft
{as a/c is low for 4dots on ILS ...... i.e. 0.15*4=0.6
therefore, 3-0.6=2.4degree}
(now, using 1 in 60 rule, ((2.4*5.26)/60)*6080=1279.2}
plz ILS hed ILS ome light on this
it is from the threshold so you have to add 50 feet ht above threshold to get ht above touchdown 1280+50 = 1330 answer is b