Q1. An a/c receives a reply pulse from a DME 1200micro sec after transsmission of the interrogation pulse.The DME has a fixed delay of 50 micro sec. the range of the a/c from the DME station is:
a.75nm
b.63nm
c.45nm
d.93nm- ans
Q2. The time interval b/w the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the a/c is 2 milli sec. the slant range is:
ans
162nm
Q3. The accuracy of DME at 100 nm slant range is within:
a.
3nm-- ans
b.4nm
c.2nm
d.1nm
{ i think ans shud be 1 nm as accuracy of dme is 1.25% of range.
so (1.25/100)*100=1.25}
plz shed some light.
Q4.A/c is following the ILS glidepath of 3degrees at an airfeild where the outer mrker is 4.2nm from the ILS touchdown point. the a/c approach speed is 130kt. the height of the a/c at the outer marker shud be:
a.1150ft
b.1200ft
c.
1310ft---ans
d.960ft
{my ans does`nt match.........i did like..........i used 1 in 60 rule...
i.e. {(3degrees *4.2)/60}*6080=1276.8.................}
i think i m doing it in wrong way
plz correct...thanks
Q5. At 5.25nm frm threshold an a/c on an ILS Approach has a display showing it to be 4dots low on a 3 degree glidepath, using an angle of 0.15degree per dot of glideslope deviation and the 1 in 60 rule calculate the height of the a/c from the touchdown.
a.1375ft
b.
1325ft
c.1450ft
d.1280ft
{as a/c is low for 4dots on ILS ...... i.e. 0.15*4=0.6
therefore, 3-0.6=2.4degree}
(now, using 1 in 60 rule, ((2.4*5.26)/60)*6080=1279.2}
plz ILS hed ILS ome light on this