Hello OwainG,
Following on from your responses to airtren's questions, excuse me checking my own understanding of the relative authorities of THS and elevator, and your 3:2 ratio. I note that your graph combines the two (Dqt and Dq) into an equivalent combined Dq.
If I understand correctly, your method results in, for examples:
THS 0 (Zero) with Elevator -15 (UP) -> equivalent Dq -15
THS -10 (NU) with Elevator 0 (Zero) -> equivalent Dq -15
THS -10 (NU) with Elevator -20 (UP) -> equivalent Dq -35
In the second example above, 100% of the HS surfaces (THS and elevator) are at -10 deg relative to the longitudinal axis of the A/C. In the third, 70% of them are at -10 deg and only 30% at -30 deg. Can you confirm that this is equivalent to a (notional) Dq of -35 (Elevator 35 deg UP) with the THS at zero, in which case only 30% of the surface area is considered to be at -35 deg?
Similarly, picking convenient figures, would:
THS -13.3 (NU) with Elevator +20 (DOWN) -> equivalent Dq zero?