PPRuNe Forums - View Single Post - VOR question
Thread: VOR question
View Single Post
Old 13th Aug 2011, 13:51
  #3 (permalink)  
gAMbl3
 
Join Date: Jul 2010
Location: Mumbai
Age: 34
Posts: 120
Likes: 0
Received 0 Likes on 0 Posts
airway width is 5nm of centre line

[/URL] Uploaded with ImageShack.us[/IMG]

tan 5.5 = 5nm / dist from VOR 'AX'

AX = 5/tan 5.5
= 5/0.096
= 52.08

So total dist = 52.08*2 = 104.16 nm

or you can use 1 in 60 rule
gAMbl3 is offline  
Reply