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Old 10th Oct 2010, 01:12
  #15 (permalink)  
QJB
 
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Now I'm even more confused haha. I think I understand JTT's explanation though. So although no work is being done on the aircraft (ie. its kinetic and potential energy remains unchanged) work is being done on the air and therefore energy from the fuel is being consumed in proportion with the rate of change of momentum.
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