Originally Posted by D Bru
Interesting reference to the V/S article in support of a “deep stall” scenario. Thanks, mm43. On the face of it doesn’t sound as improbable as that. Having said that, I cannot really follow all the mumbo-jumbo calcs.
Just to confuse you a bit more, I think mr. Squair's numbers should read:
* hcbn = 7350 – 750 ft/min X 251/60 = 7350 ft - 3138 ft = 4212 ft
Now as a 2.03625437 inHg pressure change gives approximately a 2036 ft altitude change, and as the external pressure is 1 psi
more than the cabin pressure (3), the external or aircraft altitude (hacft) is simply:
* hacft ≈ 4212 - 2036 ft = 2176 ft
2:14:21 - 2:15:14 = 53 sec
rate of descent = 2463 fpm
regards,
HN39