I'm guessing that after the stall break it would 'mush' in proportion to the amount of energy expended...like a snap roll....the control feel would be proportional to the dynamic pressure...and the loading at the stall depend at the exact speed the stall took place and increase in stall speed in a turn could be computed by
Vs[phi] =Vs*sqrt[n].... where Vs[phi] = the stall speed at bank angle 'phi' and n=1/cos[phi]
Last edited by Pugilistic Animus; 14th Jun 2010 at 07:58.
Reason: I don't know