Heres an example
For a distance of 1860 NM between Q and R, a ground speed "out" of 385 kt, a ground speed "back" of 465 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is
You do
E*H/H+O
So, 8*465/850 (Which is 465+ 385)
which gives you an answer of 4.37 this is your endurance if you wanted the distance all you do is multiply 4.37 by your outbound speed.
Hope this helps,
P.s the correct answer to the above question was 1685Nm
Here is a PET question,
Given: Distance 'A' to 'B' 2484 NM Groundspeed 'out' 420 kt Groundspeed 'back' 500 kt The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is:
so you do
2484*500/500+420 =1350nm so i divide this by my outbound speed 420 which gives me 193mins (3 hours and 12 mins) which is the right answer