Thanks Capt. Pit Bull.
Your helpful equations seem to make sense. Was surprised at how little distance is generated by two high speed aircraft (traveling at 799f/s) and turning with a angle of bank (AoB) difference of 5 degrees between the two (assuming my calculations are correct).
By the way ...
Is there a way to calculate the separation distance, if each aircraft begins the type of turns discussed,
but at different times? (for example, a turning delay of 5 seconds between each aircraft)
Traveling nearly a mile, the separation distance between two high speed aircraft is only 41 feet.
T = speed*time/circumference of turn.
Aircraft A: 20 degrees AoB: (r: 54,795); [(799)5/344,287]*360 = 4.17
Aircraft B: 25 degrees AoB: (r: 42,771); [(799)5/268,738]*360 = 5.35
Aircraft A:
Xa (20 degrees AoB)= 54,795 - (54,795 * Cos (4.17)) = 145
Ya (20 degrees AoB) = 54,795 * Sin 4.17 = 3985
Aircraft B:
Xb (25 degrees AoB)= 42,771 - (42,771 * Cos (5.35)) = 186
Yb (25 degrees AoB) = 42,771 * Sin 5.35 = 3988
Xseperation = Xa - Xb
Yseperation = Ya - Yb
Xseperation = 145 - 186 = -41
Yseperation = 3,985 - 3,988 = -3
Seperation = square root of ((Xseperation^2) + (Yseperation^2))
(-41)^2 + (-3)^2 = 1690^1/2 = 41