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Old 16th February 2010 | 19:09
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Keith.Williams.
 
Joined: Aug 2001
Posts: 775
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From: Dorset
The nose wheels are 10 m in front of the main wheels, so if the main wheels are taken as a datum, then the position of the main wheels is zero and that of the nose wheels is –10 m.

The total load and moments of each load can be calculated by adding up the loads on each wheel and using the standard equation:

Moment = load x arm.

Item...............................Load....Arm from main wheels...oment = load x arm
Nose wheel 1..................500 Kg.......-10 m....................-5000 Kg m
Nose wheel 2..................500 Kg.......-10 m....................-5000 Kg m
Left main wheel 1...........6000 Kg........Zero..................... Zero
Left main wheel 2...........6000 Kg........Zero..................... Zero
Right main wheel 1.........6000 Kg.........Zero..................... Zero
Right main wheel 2.........6000 Kg.........Zero.....................Zero

Totals.........................25000 Kg.................................-10000 Kg m


The C of G can now be calculated by using the standard equation:

C of G = Total moment /Total Mass

C of G = -10000 Kg m / 25000 kg = -0.4 m

This means that the C of G is 0.4 metre forward of the main wheels.
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