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Old 4th Oct 2009, 08:54
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ITCZ
 
Join Date: Jan 2001
Location: Australia
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Does anyone have the formula for radius of turn for an airplane (with everything in metric units)???
If you want the answer, not the formula, try this..
Aircraft Turn Information Calculator

Careful when you use the term Standard Rate. Your AIP may state that turns be made at Standard Rate (= 2min) or 25 deg AoB, whichever is lesser. It says "whichever is lesser" because 2min turn 25 AoB turn.

Skunkworks' formula works when variable is timing = 2min.

Wiki formula works when the variable is AoB.

They may be equal under certain conditions, but not always.

The following may be helpful... from "Aviation Formulary V1.24" by Ed Williams

Metric? Just work out a factor!

Turns and pivotal altitude

In a steady turn, in no wind, with bank angle, b at an airspeed v

tan(b)= v^2/(R g)
v= w R

where g is the acceleration due to gravity, R is the radius of turn and w is
the rate of turn.

Pivotal altitude h_p is given by

h = v^2/g

With R in feet, v in knots, b in degrees and w in degrees/sec (inconsistent
units!), numerical constants are introduced:

R =v^2/(11.23*tan(0.01745*b))

(Example) At 100 knots, with a 45 degree bank, the radius of turn is
100^2/(11.23*tan(0.01745*45))= 891 feet.

The rate of turn w is given by:

w = 96.7*v/R

(Example) = 96.7*100/891= 10.9 degs/sec

The bank angle b_s for a standard rate turn is given by:

b_s = 57.3*atan(v/362.1)

(Example) for 100 knots, b_s = 57.3*atan(100/362.1) = 15.4 degrees
A useful rule-of-thumb, accurate to ~1 degree for speeds up to 250
knots, is b_s= v/7 (v in knots).


The pivotal altitude is given by:

h_p = v^2/11.23

(Example) At 100 knots groundspeed the pivotal altitude is 100^2/11.23 = 890
feet.
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