mm43;
If I may enquire, for the mathematically-challenged among us, how the radius of the turn was calculated? I would just like to understand as my
very amateur reading and use of the formula from Kermode's "Mechanics of Flight" is a nominal six and three-quarter miles for a 25deg bank turn at 463kt, (532mph) groundspeed and a time of about 330 seconds for the full 180. Hand flown the turn could be made tighter of course. Speed brakes do not tighten a turn, btw, bank angle does however.
r= v^2/(g.tanθ), where;
radius is in feet, velocity is in fps, g = 32.2, Tan of 25deg = 0.4663
Found a better formula from one of our bretheren in Tech to plug into Excel:
=ROUNDUP(POWER(D2,2)/((TAN(F2/(180/PI())))*68625),3), apparently used by PAN Ops,
(Link),
D2 = TAS value
F2 = Angle of bank.
Result is in NM
If the turn began at the "LKP", the yellow circle describes an 81,000ft diameter circle, or roughly 13.5 nm.
