α prot = α max
Hey there,
The airbus in normal law:
At take off, alpha prot. is equal to alpha max for 5 seconds.
The only possible answer I can come up with is that (A320) these 5 seconds are for the transition form ground mode (direct law) to flight mode (normal law). Studying the A330 now, I have learned that this transition takes at least 10 seconds (pitch law), meaning that my above possible answer is not valid here.
Any comments will be appreciated.