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Old 14th Mar 2009, 15:46
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sycamore
 
Join Date: Jun 2002
Location: east ESSEX
Posts: 4,683
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OC619, the figures are 71% of L/O Speed by 50% TORA. It is an acceleration `checkpoint` and derived from the equations of motion; if you can`t measure/estimate 1/2 Tora,you can time it by `backworking `the POH distances.Works fine. Authority-D.Stinton ,Ex-CAA TP.

S=u+v^2 x t
S=ut + 1/2at*
V*=U* +2aS
*=sqd.^=divided, S=dist,a=accel,u=initial velocity,v= final velocity,t=time; 60
kts =100 ft/sec.
The other 50% TORA is SDA...

Last edited by sycamore; 14th Mar 2009 at 18:28.
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