So will this "wind down" method work for any calculations of this type?
Yes, it will work, if properly executed, but the wind-down method doesn't finish there. You should care to check (Step 9) that the drift resulting at Step 8 - indicated by the wind mark - is the same as the drift correction that you initially used. In this particular case it's almost exactly the same, but in general it won't, and you'll have to repeat steps 6 to 9 with an appropriately adjusted value of drift, and do so until the value of drift at Step 8 matches the one used at Step 6.
If you stop at the first iteration, you might get the heading wrong by even 10°, which is probably enough to fail the question, if not the actual navigation. Try with TR/GS = 300°/80 kt and W/V = 160°/40 kt, to see what I mean.
Deeday