Okay, thanks for the backup guys. Just after I posted, I did up some sample calculations to find the approximate angle that my Cessna and an imaginary jet make with the ground during climb-out. Obviously the Cessna's was much lower. Before though, it just seemed to me that even though the jet was climbing at thousands of feet per minute, it's forward velocity being as high as it is would make it's departure slope lower. Of course I wouldn't ever try to cut things this close, but I was just curious and wanted to know if it was possible. Thanks! <img src="smile.gif" border="0">