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Old 8th Aug 2008, 08:23
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BOAC
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"A picture is worth a thousand words"

This is very basic maths! If you get stumped by a question like this, ALWAYS sketch it out!

Mark the c of g as 'X' cm from the nose, or in front of the main wheels if you prefer.

Note down the relevant loads on front and main bogies ie 1450/24000.

Work out the moments around your 'notional' c of g, 'X'.

Since the a/c does not tip on its tail, they must be equal

With X marked from nose:-
1450 x X=(10-X) x 24000 (10 is distance between legs)

Solve for X (metres)
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