Remember you can also use what's left of the drift calculation to work out the head and tailwind component to give you a G/S.. .. .Example:. .. .Wind 240/30 kts. Max drift for 90 kts TAS = 20 degs. . .. .Assume your diversion track means you calculate that you will use the clock code to assume a factor of 0.6 for the drift. This leaves you with 0.4, which you then apply to the number of KNOTS (not degrees) of the windspeed to give you a tailwind or headwind component (you should be able to work out which!). In the above example that component will be 30 x 0.4 which is 12 kts in round numbers. Your G/S will therefore 102 or 78 kts.. .. .To work out EET to the new destination, I find it is easiest to divide the G/S by the distance. Say you have a G/S as above of 102 kts and the distance is 50nm. 50 goes into 102 just over twice, so it will take you just under half an hour to travel the distance. If the distance were 24 miles then the same G/S would give an EET of approx 14 mins. It's close enough for PPL estimation and a lot easier than fiddling about with whizz wheels while trying to maintain height and heading and keep a lookout.