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Old 3rd March 2008 | 10:55
  #7 (permalink)  
mcgrath
 
Joined: Apr 2003
Posts: 8
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From: somewhere
My initial thinking was as per SkyCamMK.

Though found the formula h2 = h1 + 221.1*T*(log P1 - Log P2) for instances where pressure difference is greater than 50mb, where

h1 = known height
h2 = required height
T = mean temp in K
P1 = pressure at h1
P2 = pressure at h2

filling these in get h2 = 0 + 221.1*275*(log 1025- log 950) = 2006.5ft

JBA, using 96T/P if use the average T of 275 and average P of 987.5mb get a height change per mb of 26.74 ft and the multiply this by 75 (1025-950) get 2005.1ft. Just wondering did you miscalculate?

Like SkyCamMK will watch with interest.
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