Cracked it ! The equal time point is the the point where onward to the destination is the same time as return to the departure.
Using the symbols of the equation that means:
ETP/H = (D-ETP)/O (time = dist/speed)
so ETP/H = D/O - ETP/O (expanding RHS)
and ETP/H + ETP/O = D/O (adding ETP/O to both sides)
and (OETP + HETP)/OH = D/O (bringing the LHS to a common denominator)
so OETP + HETP = DOH/O = DH (multiplying by OH)
and ETP(O+H) = DH (factorising the LHS)
therefore ETP = DH/(O+H). QED.
Well it kept me happy for a couple of days !
Last edited by puntosaurus; 27th January 2008 at 16:06.