Just had a look at questions 2 & 3 and I agree with the answers given previously.
Q2. Using m/M = d/D m=? M=2200 d=0.15m D=3m
m = Md/D
m = 2200 x 0.15 / 3 = 330/3 = 110Kg to move from FWD to AFT cargo hold
Q3. Total weight through nose gear = 1000Kg. Total weight through main gear = 24000Kg. Therefore total aircraft weight is 25000Kg.
Using the main gear position as a datum, the nose gear turning moment is 1000Kg x -10m = -10000Kgm.
CG position = moment/weight = -10000/25000 = -0.40m = -40cm i.e 40cm forward of main gear. Answer b.
When doing these remember to use the correct signs for positive (clockwise) & negative (counterclockwise) turning moments with respect to the datum.
Noz
Last edited by Nozwaldo; 27th September 2007 at 12:31.