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Old 11th Aug 2007, 18:21
  #1487 (permalink)  
slip and turn
 
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Originally Posted by originally Gigajoules, I think?
Energy is given by E=mv^2, where m = mass and v=velocity. So, the calculation gave the right answer but using F=ma will not give that answer.
Originally Posted by ELAC
Gigajoules,

Thanks for the correction. Post edited to reflect the correct formula.
I don't think it has affected anything you guys have calculated so far as you have only been presenting fractional comparisons based on known tabulated constants I think, but when I went to school the Kinetic Energy of a moving mass m at constant velocity v was stated as 1/2 mv^2. This is not to be confused with E=mc^2 which is Einstein's Energy Mass equivalence formula!

Another simple straight line event formula from schoolbook physics that might help is
s = ut + 1/2 a t^2

s = distance travelled
u = initial velocity
a = acceleration (or deceleration)
t = time period under acceleration/deceleration

and you should then be able to get results consistent with F=ma if you can estimate the resultant straight line forces involved with the brakes, the right engine forward thrust and the left engine reverse thrust.

Probably easiest to convert everything to SI units before you start.
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