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Old 10th Aug 2007, 15:38
  #150 (permalink)  
Matthew Parsons
 
Join Date: Feb 2005
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waspy, I should have mentioned that. Thanks. The tip speed, rotational speed and rotor length only worked if it was a radius, as it was used later in BGring's post.

BGring. The g used later on is as in G-force, which isn't a force, which unfortunately leads to more misunderstanding. 'g' is a unit of acceleration based on the gravitational pull of the earth. With non-spherical shape of the planet, the mass distribution, and the varying rotational speeds based mostly on latitude, the value of g is not constant. However, it changes so little that conventionally we use 1 g = 9.81 m/s^2. So dividing your answer of 17,433.485 by 9.81 you get 1777 g (not grams).

You can use g by itself, but to get the force you can either go back to the CF equation you started with or you can multiply g by the weight of the object. To get the weight of a 5g object, you multiply it by the acceleration due to gravity (9.81 m/s^2) and you get 0.005kg x 9.81 m/s^2 = 0.049N, or 1/20 of an apple ~one small bite.

Matthew.
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