1/2
? x
Rhox
(V squared) is derived by integrating the
rate of change of the
momentum.
Since the
momentum is
Rho x
V, if you
integreate it (using integral calculus) you get the
1/2 x
Rho x
(V squared).
it is that the
area? under the
momentum vs
V curve is calculated by the formula.
The Purple and Greay parts confuse me. (Gentle reminder, Why 1/2)
Please remember I want to be
but curently I am
so could you dumb it down a little(Lot) for me.
Edit 1/2 hour later
Or is it
1/2 x Rho x Vsquared is derived by integrating the rate of change of the momentum.
Since the momentum is Rho x V, if you integreate it (using integral calculus) you get the 1/2 x Rho x Vsquared.
it is that the area? under the momentum vs V curve? is calculated by the formula.
Changes being the Green bits
end Edit
I may well be a Lost cause 