Funnily enough, Pilotmike, that is presactly the answer I get using my quoted equation.
I wonder if you are confused by my not enclosing the bottom line of the equation in brackets, i.e. (gs out + gs home).
I was trying to keep things as simple as possible, and I thought writing it like that might complicate the issue. I am assuming that you thought I thought the gs home on the bottom line should be added to the result of the rest of the equation, but that is impossible because you would be adding speed to a distance.
My equation is correct, and in my opinion the simplest to use. However, that's only my opinion.