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5th July 2007 | 19:28

#6 (permalink)

DBate

Joined: Jan 2003

: ATPL

Posts: 279

Likes: 17

From: Europe

Capt. Slow

Oh, sorry for that! You are absolutely right - it is gradient, not a slope...

In that case, to find the rate required, multiply the gradient by the GS (or rather TAS).

12% x 540 = 6480'/min.

Regards

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