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27th Apr 2007, 04:37

#564 (permalink)

Abu Bebo

Join Date: Jan 2006

Location: England

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Wind trigonometrically

For your peace of mind:

cos 3 = B/101 => B=100.86, so C=122-B = 21.14
sin 3 = D/101 => D=5.2859
tan a = D/C = 0.25 => a=14.04 degrees
D^2+C^2=A^2, so A=21.789
therefore wind direction is 138-14.04=124 degrees; wind speed=22 knots
Regards
AB

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