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Old 2nd Apr 2007, 02:06
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Old Smokey
 
Join Date: Jun 2004
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Sorry ranklein, if I seemed rude in not answering a question that was (loosely) addressed to me, aee190 has done a nice job of answering it, and added some good thought of the practical application of Altimetry rules.

With respect to your earlier question, 3.28 ft/M is fine for day to day calculations, I prefer to divide by 0.3048 (which is an exact conversion) rather than multiplying by 3.280839895.... (which is a surd and not an exact conversion), but that's only because I'm pedantic.

The tone of your questions suggest that you might be studying for an exam, beware!, some examiners are pedants (like me ), and in your question....

Obstacle : 4730 M / .3048 = 15518.4 ft,
QNH Corr'n : (1013.25 - 995) = 18.25 X 27 = 492.8 (more if you use 27.5)
Minimum F/L = 15518.4 + 492.8 +1500 = 17511.2 ft.

Now, as aee190 has indicated, F/L 190 would be the correct answer in a U.K. exam, but it's JUST above F/L 175 by 11.2 ft, so if Outside Controlled Airspace, the correct answer would be F/L 195. Beware pedantic exam questions!

Interesting to see a poster from the U.S.A. with an interest in Flight Levels below F/L 180.

Regards,

Old Smokey
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