Towser's answer is correct. To put it in another way:
Heading = 158 (T)
8 Degrees port drift => Track made good = 158 - 8 = 150 (T)
To parallel track of 153 (T), we need to turn 3 degrees to the right.
Therefore, Heading = 158 + 3 = 161 (T)
Magnetic heading = 161 + 11 = 172 (M)
But from the theoretical point of view, I would think the most accurate method would be to find out what the wind velocity is (provided you have the TAS and groundspeed), put in the track of 153, solve for the heading using your computer and add variation to get your magnetic heading. Cheers.
9V