Simplifying Differential Equations
I don't know whether this helps, but the square of the first differential reminds me of v-squared, or (ds/dt)**2. In which case it can help if we keep it as v-squared, v**2, and write the second differential, d2s/dt**2 (which is dv/dt), as v.dv/ds.
With the v-squareds that crop up in many aero problems, this often rescues the situation by giving you a linear first-order differential equation in v and s rather than a non-linear one in v and t (or even a second order non-linear one in s and t).
Any help?
Last edited by D120A; 24th February 2007 at 13:27.
Reason: Clarity (hopefully!)