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Old 25th December 2006 | 17:38
  #18 (permalink)  
Dave_Jackson
 
Joined: Apr 2003
Posts: 1,635
Likes: 1
From: Vancouver, BC, Canada
IFMU,

You make good points. The blade root just seem to have a larger diameter than what should be required for the radial bearings or the blade strength. All very interesting.


Mart,
Dave, you recover from blade stall in a helicopter by crashing into the ground
Forget the generalistic 'statement of fact'. Please give a reason why a helicopter with 'absolutely' rigid rotors will crash into the ground.

Why do you think autogyros spin up their blades before flying?
HOW do you think autogyros spin up their blades before flying? (excluding prerotors)

A single teetering rotor has dihedral as a result of the aero-gyroscopic forces, and "rigid" rotors are not so far removed in behavior (but feel less stable). The only problem is rotor dynamic response, and the fact that the cyclic does not auto centre. The Honeywell SPZ7600 system Nick sited takes care of that.
What are you trying to say?

An absolutely rigid rotor is just not achievable
Who says that an 'Absolutly' rigid rotor is not achievable.


slowrotor,

Just an observation. The vertical distance from rotor to fuselage (center of gravity and drag) is decreased as the rotor's rigidity is increased. The picture of the Hummingbird shows a rotor that is very close to the fuselage.

I will list out a few reasons why the interleaving MAY be attractive.


Dave

Last edited by Dave_Jackson; 25th December 2006 at 18:28. Reason: Politeness forbids a response.
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