Tis simple really.........
Drift angle = 14 degrees. 225knots divided by 60 = 3.75.
14 (degrees) by 3.75 = 52.5 knots crosswind component.
12 minutes is a fifth of an hour. 50nm in 12 minutes is 250knots therefore.
TAS 225 knots, means 25 knots tailwind component.
Even a rough guess gives a triangle with one side twice as long as the other. The hypotenuse (can't spell it) will be longer than the longest side by a small amount. Let's guess at - side one=52.5, side two=25, hyp then=60??
A right angled triangle with one side about twice as long as the other gives an angle of about 25 degrees. Since there is more crosswind than tailwind, and the drift is to the right, the wind is from about 25 degrees behind the left wing. Heading is 301 degrees, left wing is pointing at 211 degrees, less 25 gives 186 degrees. So my guess is 186M at 60 knots. Less variation makes
181/60. D is the closest answer.
Sure tis the way we used to do it in the old days. Back when we walked in bare feet uphill both ways for school and kept a piece of coal in our back pocket to keep us warm.
If you want to be more accurate than this brain work, CRP is your only man.
In fact, my way is absolute rubbish for accuracy if the truth be told, but tis handy for real life!