Originally Posted by
XPMorten
Right, as you can see on the first illustration,
and on the Wieselberger diagram, the effect starts at about
one span altitude. A high AR wing vortex will probably have
a bigger radius than a low AR wing since the lateral airflow
has a bigger distance to travel from root to tip. So it will get
in conflict with the ground sooner.
The percentage of drag reduction in the two cases will offcourse be the same,
but the F104 will loose drag faster and more than the glider.
M
I believe you're diagram, I just don't understand why.
A high AR wing has smaller induced drag generally, so how does this equate to bigger radius? With a glider with extremely long wings, for example, the pressure differential between top and bottom wings will be smaller than one with less wingspan. And this higher AR wing creates a bigger radius vortex??
And lateral airflow travels from root to tip??
The percent of drag losses from tips is the same?? Can't see why that would be the case either.
Anyone?