Thank you.
So since SAT is displayed in degrees C, my cheat sheet ( for quick reference)should read like this:
TAT = SAT + 273 X (1+.2*M^2) - 273?
So if:
mach = .74
SAT = -54 deg C
Then:
-54 + 273 X (1 + .2 X .74^2) - 273 = - 30.015 deg C, or about 23.085 deg C of ram rise. Is that correct?
Sorry to drag this out. I just want to make sure I get it right.
Thanks for the clarification.
Westhawk