Originally Posted by chornedsnorkack
500 feet divided by climb gradient of 5% is 10 000 feet. Less than 5000 m.
Finding the climb gradient itself, from simple physics viewpoint... you could take thrust/weight, substract drag/lift... and wouldn´t you thus arrive at the climb gradient?
Of course, presumably there are required safety margins scattered all around the computations!
So regarding my question:
with a climb gradient of 5% the aircraft will reach 500 ft after traveling 3200m, after traveling 5000m the aircraft should be at (500+274) 774 ft.?
160 m (500ft) / 5% = 3200m
5000-3200 = 1800m
x / 5% = 1800m
x = 90 m (274ft) (conversion m x 3,045 = ft)
correct?