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Clearly doin' something stooopid..
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1st Apr 2006, 10:42
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BEagle
Join Date: May 1999
Location: Quite near 'An aerodrome somewhere in England'
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I'm sure that sin@ = (T/W) - (Cd/Cl) is correct; in which case the answer would seem to be inv sin (120/(50 x 9.81)) - (1/12)
i.e. inv sin (0.2446 - 0.0833) = inv sin 0.1613 = 9.28 deg.....
What were their answers?
BEagle
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