Re: Help on Dynamic pressure formula
Look at the dimensions of Density and Velocity.
(sorry no superscript)
rho = Kg.M-3
V = M.S-1
V2 = M2.S-2
so dynamic pressure units can be stated as
Kg.M-3.M2.S-2
Simplifies to
Kg.M-1.S-2
We are looking to equate the dimensions to Pa, = N.M-2
Can we rearrange the units to make it fit? Use Newtons second law.
F = MA
or better, M = F / A
so Kg = N / (M.S-2)
so Kg = N.M-1.S2
Substitute for mass units in our earlier formula Kg.M-1.S-2
yields N.M-1.S2.M-1.S-2
Seconds cancel out, leaves dymnamic pressure units:
N.M-1.M-1 i.e. N/M2
Hope thats what you wanted. I think its right, though its late.
(c) PB